How to return data from PHP to a ajax function

Question

Hi I am currently learning php and I am trying to get data from php file using the below script but i am not getting any response

        $.ajax({
            type: 'POST',
            url: "mark_mod.php",
            data: data_set,
            dataType: "JSON",
            success: function(data) { 
                alert("Response : " ); // not triggering
            }
        });

my php return stmt

refer stackoverflow.com/a/57820130/6309457 OR stackoverflow.com/a/52404102/6309457 — Devsi Odedra
– Devsi Odedra, Commented Sep 24, 2019 at 9:46
Welcome. You should post the .php script that doesn't seem to work — user8034901
– user8034901, Commented Sep 24, 2019 at 9:48
please post your php code or check yourself are you echo or print the response — user11988937
– user11988937, Commented Sep 24, 2019 at 9:51
<?php $retJason = '[ { "userid":"'.$out_userid.'", "username":"'.$out_username.'", "address":"'.$out_address.'" } ]'; echo $retJason; ?> — RAY
– RAY, Commented Sep 24, 2019 at 10:20

htmler · Accepted Answer · 2019-09-24 10:07:05Z

0

There might be problems with File URL or file access. You can use complete callback to check request for errors like that:

 $.ajax({
    type: 'POST',
    url: "mark_mod.php",
    data: data_set,
    dataType: "JSON",

    success: function(data) { 
        alert("Response : " );
    },

    // This method will be fired when request completes
    complete: function(xxhr, status) {
        alert("Status code: " + status);
    }

});

If the status code is not success that means there is something wrong with your request. You can check more callback options here.

It doesn't matter whether you use return or echo in your PHP file. The success method must get a call if it's fine. However, if you use return instead of echo, nothing will append to your request's data.

edited Sep 24, 2019 at 10:07

answered Sep 24, 2019 at 9:54

htmler

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Comments

Vir-Dev · Accepted Answer · 2019-09-24 15:46:16Z

0

On the other hand, The PHP response will include in your 'data' variable in the function success.

You need use data in the assync function success

success: function(data) { 
    alert("Response : " + data);
},

answered Sep 24, 2019 at 15:46

Vir-Dev

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Comments

RAY · Accepted Answer · 2019-09-26 10:35:41Z

0

Thanks for your Responses. I got the Solution to my problem. It seems since Ajax is asynchronous... its taking time to receive the resultant echo value from my php file. so I had to synchronize my Jquery using async : False.

answered Sep 26, 2019 at 10:35

RAY

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Comments

Nipu · Accepted Answer · 2019-09-26 10:41:35Z

0

$(function(){
$('#formID').on('submit',function(){
const data_set={
name:"Nipu chakraborty",
"phone":"01783837xxx"
}       
$.ajax({
            type: 'POST',
            url: "mark_mod.php",
            data: data_set,
            dataType: "JSON",
            success: function(data) { 
                alert(data);
            }
        });
   });
});

answered Sep 26, 2019 at 10:41

Nipu

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