sort array object using other array

Question

not able to sort array object according to given array can you please help me out!!

const data = [ {
    parent_email: '[email protected]',
    childSurName: null,
    childFirstName: null,
    id: 22},
{
    parent_email: '[email protected]',
    childSurName: null,
    childFirstName: 'Sachidanand',
    id: 31},
{
    parent_email: '[email protected]',
    childSurName: null,
    childFirstName: null,
    id: 26}];

const order = [ 31,26 ];

const sorted = data.sort((a, b) => (
     order.indexOf(a.id)  - order.indexOf(b.id)
));

console.log(sorted)

I need sorted result like my second array are and then after other data :

 [ {
    parent_email: '[email protected]',
    childSurName: null,
    childFirstName: 'Sachidanand',
    id: 31},
 {
    parent_email: '[email protected]',
    childSurName: null,
    childFirstName: null,
    id: 26}
{
    parent_email: '[email protected]',
    childSurName: null,
    childFirstName: null,
    id: 22},
];

but i am getting below result not getting proper sorted data:

[{
    parent_email:"[email protected]",
    childSurName:null,
    childFirstName:null,
    id:22
 },
 {
    parent_email:"[email protected]",
    childSurName:null,
    childFirstName:"Sachidanand",
    id:31
 },
 {
    parent_email:"[email protected]",
    childSurName:null,
    childFirstName:null,
    id:26
 }]

"22" !== 22 so your indexOf doesn't find the IDs

VLAZ
– VLAZ

2019-09-30 09:21:32 +00:00
Commented Sep 30, 2019 at 9:21 — VLAZ
– VLAZ, Commented Sep 30, 2019 at 9:21
@VLAZ ok let me edit question then.

dev
– dev

2019-09-30 09:25:05 +00:00
Commented Sep 30, 2019 at 9:25 — dev
– dev, Commented Sep 30, 2019 at 9:25

Code Maniac · Accepted Answer · 2019-09-30 09:33:22Z

2

You can use a Map and place values along with priority inside Map and then sort,

Note:- Also don't forget to keep the search value and key of same type

const data = [{parent_email: '[email protected]',childSurName: null,childFirstName: null,id: 22},{parent_email: '[email protected]',childSurName: null,childFirstName: 'Sachidanand',id: 31},{parent_email: '[email protected]',childSurName: null,childFirstName: null,id: 26}];

const order = ['31', '22'];
const mapper = new Map(order.map((v, i) => [parseInt(v), i + 1]))

const sorted = data.sort((a, b) => (
  (mapper.get(a.id) || Infinity) - (mapper.get(b.id) || Infinity)
));

console.log(sorted)

edited Sep 30, 2019 at 9:33

answered Sep 30, 2019 at 9:28

Code Maniac

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Comments

user2039981 · Accepted Answer · 2019-09-30 09:24:40Z

0

const sorted = data.sort((a, b) => order.indexOf(a.id.toString()) - order.indexOf(b.id.toString()) );

id must be converted toString.

Alternatively, change

 const order = [ '31','22' ];

to

 const order = [ 31,22 ];

answered Sep 30, 2019 at 9:24

user2039981

Comments

mzfr · Accepted Answer · 2019-09-30 09:57:28Z

0

The problem is because of id 22. It does not exist in order array and indexOf function return -1 for this id. It means the top priority, so it appears in the first place of result array. You should handle ids that do not exist in the order array. For example (for sorting) you can do as below:

const sorted = data.sort((a, b) => {
    let aindex = order.indexOf(a.id);
    let bindex = order.indexOf(b.id);
    if(aindex === -1) return 1;
    if(bindex === -1) return -1;
    return aindex  - bindex;
});

answered Sep 30, 2019 at 9:57

mzfr

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