I'm generating a random number in the range of 65 to 90 (which corresponds to the byte representations of uppercase characters as bytes). The random number generator returns an integer value and I want to convert it to a byte.
When I say I want to convert the integer to a byte, I don't mean the byte representation of the number - i.e. I don't mean int 66 becoming byte [54 54]. I mean, if the RNG returns the integer 66, I want a byte with the value 66 (which would correspond to an uppercase B).
Use the byte() conversion to convert an integer to a byte:
var n int = 66
b := byte(n) // b is a byte
fmt.Printf("%c %d\n", b, b) // prints B 66
You should be able to convert any of those integers to the char value by simply doing character := string(asciiNum) where asciiNum is the integer that you've generated, and character will be the character with the byte value corresponding to the generated int
string will convert the integer to a string data type, which is a []byte underneath, so it's kind of overkill if the OP just wants one byte.
character[0]... still, just using byte type conversion is cleaner.byte to convert is preferred.
byte(i)or[]byte(string(i))to set an int to a byte. See stackoverflow.com/a/62737936/12817546.int(b)orint(b[0])to set a byte to an int. See stackoverflow.com/a/62725637/12817546.