I'm trying to sort an array of strings based on an array of objects. (The array will not have the same amount of items the object has.)
Here's the code:
const myObject = [
{
title: 'Some string'
},
{
title: 'another string'
},
{
title: 'Cool one'
}
];
const array = ['Cool one', 'Some string']; // Sort this array based on 'myObject'
You can generate a table of indices by which to sort your array like this:
const myObject = [
{ title: 'Some string' },
{ title: 'another string' },
{ title: 'Cool one' }
];
const indices = Object.fromEntries(
myObject.map(
({ title }, index) => [title, index]
)
);
const array = ['Cool one', 'Some string'];
array.sort((a, b) => indices[a] - indices[b]);
console.log(array);You can use reduce & findIndex. Inside reduce callback function use findIndex to check if the element exist in myObject. If so then get the index and using this add the value in accumulator array
const myObject = [{
title: 'Some string'
},
{
title: 'another string'
},
{
title: 'Cool one'
}
];
const array = ['Cool one', 'Some string'];
let newArray = array.reduce(function(acc, curr) {
let findIndex = myObject.findIndex(a => a.title.toLowerCase().trim() == curr.toLowerCase().trim());
if (findIndex !== -1) {
acc.push(myObject[findIndex])
}
return acc;
}, []);
console.log(newArray)
I think you can use Array.findIndex() to help you out on this one, in conjunction with Array.sort()
const objectArray = [
{ title: 'Some string' },
{ title: 'another string' },
{ title: 'Cool one' }
]
const stringArray = [
'Cool one',
'Some string'
]
const sortFromObject = (a, b) => {
// get the indexes of the objects
const idxA = objectArray
.findIndex(obj => obj.title === a)
const idxB = objectArray
.findIndex(obj => obj.title === b)
// if it comes first in the object array,
// sort this item up, else sort it down
return idxA - idxB
}
stringArray.sort(sortFromObject)