JavaScript - Add function to prototype using array notatio

Question

Is it possible to do something like that?

Foo.add_function = function (callback_name, callback_function) {
    this.prototype[callback_name] = callback_function;
}

I need to add a function to prototype in array notation. Thank you.

@thom So you want to be able to do this: Foo.add_function('blah', function() { ... }); instead of this: Foo.prototype['blah'] = function() { ... };? — Šime Vidas
– Šime Vidas, Commented May 2, 2011 at 17:36
@thom Because adding methods to Foo.prototype only makes sense if you're going to use those methods later. You create instances of Foo like so: var foo1 = new Foo(); and then call the prototype methods on those instances: foo1.blah(). If Foo is not a function, you cannot make instances of it, so having a prototype object is pointless. — Šime Vidas
– Šime Vidas, Commented May 2, 2011 at 17:45
@thom: prototype is a property of a function. Things that aren't functions do not have a prototype property. — SLaks
– SLaks, Commented May 2, 2011 at 17:50

SLaks · Accepted Answer · 2011-05-02 17:29:15Z

1

Yes.
A prototype is a normal object; that will work fine.

Note that this will only work if this is a function; otherwise, prototype won't exist.

answered May 2, 2011 at 17:29

SLaks

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Comments

Milimetric · Accepted Answer · 2011-05-02 17:31:23Z

0

Apparently, yes:

jsfiddle is great, you should check it out when you want to test out simple stuff like this.

answered May 2, 2011 at 17:31

Milimetric

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