Count each string in an string

Question

I am having a text..

text= ''' One of the best ways to make yourself happy in the present is to recall happy times from the past memories ''' I want to match each word in the match list and count their occurrence.

match=['happy birthday to me' , 'john sent me the memo app' , 'self time' , 'call the rom']

Example- In first iteration i.e, happy birthday to me...

happy is counted 2 times , birthday is counted 0 times , to is counted 2 times , me is counted 1 time. ('me' in memories)

I want the result as-

happy(2) birthday(0) to(2) me(1)
john(0) sent(1) me(1) the(3) memo(1) app(2)
self(1) time(1)
call(1) the(3) rom(1)

I tried this...

for textmatch in match:
    num=text.count(textmatch)
    textmatch= textmatch +'(' + str(num) +')'
    print(textmatch)

But this doesnt do the job.

Joe Iddon · Accepted Answer · 2019-10-30 17:04:59Z

You need to iterate over each word in the match strings. This can be achieved by splitting it (on spaces).

The other nifty trick is to print out each word with the optional end argument set to just a space (' '). This means that they all stay on one line until a plain print() call is made which moves to the next line.

for textmatch in match:
    for word in textmatch.split():
        num=text.count(word)
        print(word + '(' + str(num) + ')', end=' ')
    print()

Test in the interpreter:

>>> text= ''' One of the best ways to make yourself happy in the present is to 
...            recall happy times from the past memories '''
>>> 
>>> match=['happy birthday to me' , 'john sent me the memo app' , 'self time' , 'call the rom']
>>> for textmatch in match:
...     for word in textmatch.split():
...         num=text.count(word)
...         print(word + '(' + str(num) + ')', end=' ')
...     print()
... 
happy(2) birthday(0) to(2) me(2) 
john(0) sent(1) me(2) the(3) memo(1) app(2) 
self(1) time(1) 
call(1) the(3) rom(1)

Austin · Accepted Answer · 2019-10-30 17:05:25Z

1

You can do a list comprehension to form a list of words and their frequency:

text= ''' One of the best ways to make yourself happy in the present is to recall happy times from the past memories '''
match=['happy birthday to me' , 'john sent me the memo app' , 'self time' , 'call the rom']

print([[(y, text.count(y)) for y in x.split()] for x in match])

answered Oct 30, 2019 at 17:05

Austin

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2 Comments

Ravi S. Ranjan Over a year ago

It works perfectly.. But can you make this more concise to read..Like happy(2) birthday(0) to(2) me(2)

Austin Over a year ago

@RaviSRanjan, If you have to do any manipulation on the result, you need to sacrifice the readability.

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