Java - Get substring from 2nd last occurrence of a character in string

Question

My input: "professions/medical/doctor/"

My desired output: "doctor"

I have the following solution but it is not a one-liner:

String v = "professions/medical/doctor/";
String v1 = v.substring(0, v.length() - 1);
String v2 = v1.substring(v1.lastIndexOf("/")+1, v1.length());
System.out.println(v2);

How can I achieve the same in a one-liner?

You can use a regex to achieve the same. Something like \/\w+\/$ would give you the match. — Leni
– Leni, Commented Oct 31, 2019 at 2:16

Tim Biegeleisen · Accepted Answer · 2019-10-31 02:24:47Z

4

I would probably use String#split here (requiring either a one or two line solution):

String v = "professions/medical/doctor/";
String[] parts = v.split("/");
String v2 = parts[parts.length-1];
System.out.println(v2);

If you know that you want the third component, then you may just use:

System.out.println(v.split("/")[2]);

For a true one-liner, String#replaceAll might work:

String v = "professions/medical/doctor/";
String v2 = v.replaceAll(".*/([^/]+).*", "$1");
System.out.println(v2);

answered Oct 31, 2019 at 2:24

Tim Biegeleisen

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3 Comments

Sam Orozco Over a year ago

I like the split technique here. Split into segments and pull out which one you want.

Scary Wombat Over a year ago

I like split too. Banana split - more so.

Tim Biegeleisen Over a year ago

@ScaryWombat Now just stop that! You're making me hungry.

iluxa · Accepted Answer · 2019-10-31 02:25:53Z

1

Use lastIndexOf(str, fromIndex) variant:

String v2 = v.substring(v.lastIndexOf('/', v.length() - 2) + 1, v.length() - 1);

edited Oct 31, 2019 at 2:25

answered Oct 31, 2019 at 2:22

iluxa

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2 Comments

activelearner Over a year ago

I get this error: java.lang.StringIndexOutOfBoundsException: String index out of range: -1 @iluxa

iluxa Over a year ago

My bad, misunderstood the fromIndex. Updated the answer, try that

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