Pythonic solution for conditional arguments

Question

I have a below function where infile is the parameter of func. Now I want to perform the below operation.

If infile = default, then do, df = pd.read_csv("/path/to/the/file/given/a.csv) else, read the file path given to the infile.

def func(infile):
  if infile == default:
      df = pd.read_csv("/path/to/the/file/given/a.csv)
  else:
      df = pd.read_csv(infile)

This approach is working fine

What is the value of default?

Steven
– Steven

2019-10-31 03:48:17 +00:00
Commented Oct 31, 2019 at 3:48 — Steven
– Steven, Commented Oct 31, 2019 at 3:48

henrywongkk · Accepted Answer · 2019-10-31 03:27:13Z

1

Default parameter in Python function definition works like below:

def func(infile="/path/to/the/file/given/a.csv"):
    df = pd.read_csv(infile)

When one or more parameters have the form parameter = expression, the function is said to have “default parameter values.” For a parameter with a default value, the corresponding argument may be omitted from a call, in which case the parameter’s default value is substituted. If a parameter has a default value, all following parameters up until the “*” must also have a default value — this is a syntactic restriction that is not expressed by the grammar.

edited Oct 31, 2019 at 3:27

answered Oct 31, 2019 at 3:21

henrywongkk

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2 Comments

Shanoo Over a year ago

I need to have an option for infile parameter. For example, if infile ='Y', do this else do that

henrywongkk Over a year ago

just implement as what you said, what's the problem you're facing?

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