Python logger exception to file

Question

I use logging. The logger writes to file only. (and not to standard output.) In some cases logger raises exception from inside a logger method. My goal is say to logger not to write anything on to standard out/err, in case of any error at all. All internal exception should be handled internally, and should be written into the log file.

Details:

My logger raised charmap error. This particular issue has been solved based on this thread. But I afraid of that in a specific case, other exception can occur (file IO error, etc), on the field, which is very frustrating, that the logger fails, while the system works. I want to ensure that the logger don't print anything on standard out/err at all.

My expected behavior is something like this:

try:
    logger.debug('Some error maker')
except:
    try:
        logger.debug('Error during log')
    except:
        pass

Just, of course, I don't want to write try-except around all of my logger statement.

Is there anything similar feature in the logger? Something quiet mode?

The example code is the expected behavior, which want to be achieved using some parameters of the logger. — betontalpfa
– betontalpfa, Commented Oct 31, 2019 at 16:47
i don't understand, maybe you can use a finally clause then finally: logger.debug("This always logs") — Chris_Rands
– Chris_Rands, Commented Oct 31, 2019 at 16:50
I don't want to write try-except around all of my logger statement. I search a parameter, which do this behavior automatically — betontalpfa
– betontalpfa, Commented Oct 31, 2019 at 16:54

mdgm · Accepted Answer · 2019-10-31 17:31:26Z

1

What about a function like this?

def my_logger(thing_to_log):
    try:
        logger.debug(thing_to_log)
    except Exception:
        try:
            logger.debug('Error during log')
        except Exception:
            pass

In the rest of the code you'll only need:

my_logger(thing_to_log)

answered Oct 31, 2019 at 17:31

mdgm

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Comments

sophros · Accepted Answer · 2020-04-01 09:39:17Z

0

To improve over @mdgm answer you can use the built-in features of logging to log stack trace and details of the exception:

def my_logger(thing_to_log):
    try:
        logger.debug(thing_to_log)
    except Exception:
        try:
            logger.debug('Error during log', exc_info=True, stack_info=True)
        except Exception:
            pass

answered Apr 1, 2020 at 9:39

sophros

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