How filter simple multidimensional array with only numbers

Question

I have a multidimensional array like this: let arr = [ [1,2,3], [3,4,6], [4,5,7], [8,9,3]];

and I need to use only a filter function for filtering this array. I must filter the array and create a new array from the current inner arrays which contain the number 3:

let myArr = [ [1,2,3], [3,4,6], [4,5,7], [8,9,3]];
function getVal(value, arr){    
    for(let i in arr){
        for(let j in arr[i]){
            if(arr[i][j] == value){
                return true;
            }
        }
    }

}

let newArr = myArr.filter(getVal(3, myArr));

My code is not working. Actually, it's working, but I don`t see any result.

The expected result is like this:

newArr = [[1,2,3], [3,4,6], [8,9,3]];

All I have found are filter methods with objects.

Nina Scholz · Accepted Answer · 2019-11-02 20:52:25Z

3

You need a different style of the callback.

const contains = v => a => a.includes(v);

var array = [[1, 2, 3], [3, 4, 6], [4, 5, 7], [8, 9, 3]],
    result = array.filter(contains(3));

console.log(result);

edited Nov 2, 2019 at 20:52

answered Nov 2, 2019 at 19:35

Nina Scholz

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Comments

Eriks Klotins · Accepted Answer · 2019-11-02 19:36:30Z

1

Assuming that it is 2 dimensional array. Use indexOf to check inside arrays:

myArr.filter((a)=> { return a.indexOf(3)>=0})

answered Nov 2, 2019 at 19:36

Eriks Klotins

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Comments

M.Amer · Accepted Answer · 2019-11-02 19:38:20Z

0

cont result = arr.filter(a => a.includes(3));

answered Nov 2, 2019 at 19:38

M.Amer

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1 Comment

Mark Rotteveel Over a year ago

Please don't post only code as an answer, but include an explanation what your code does and how it solves the problem of the question. Answers with an explanation are generally of higher quality, and are more likely to attract upvotes.

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