php get array index of object having specific key value

Question

I need to test if a specific key/value exists and then return the array index that the key/value is a member of without having to loop through each element and/or levels of the array. Is this possible?

 [0: 
     { regional:
          [ 0 :
               {
               ID: 1000
               someInfoA : valueA
               someInfoB : valueB
               }
          ]
          [ 1 :
               {
               ID: 1001
               someInfoA : valueA
               someInfoB : valueB
               }
          ]
          [ 2 :
               {
               ID: 1002
               someInfoA : valueA
               someInfoB : valueB
               }
          ]
          [ 3 :
               {
               ID: 1003
               someInfoA : valueA
               someInfoB : valueB
               }
          ]
     }
     { national : 
       [ ... ]
       [ ... ]
     }
]

In this data example, I need to see if ID: 1002 exists and if it does, return the array index: [2], if not return false. i have seen various ways of just determining if the key/value exists but I haven't seen a non-loop method for returning the array index it belongs to.

Vladan · Accepted Answer · 2019-11-04 17:42:21Z

5

You can do a combination of array_column() and array_search(). Have a look here.

$records = [
    [
        'id' => 2135,
        'first_name' => 'John',
        'last_name' => 'Doe',
    ],
    [
        'id' => 3245,
        'first_name' => 'Sally',
        'last_name' => 'Smith',
    ],
    [
        'id' => 5342,
        'first_name' => 'Jane',
        'last_name' => 'Jones',
    ],
    [
        'id' => 5623,
        'first_name' => 'Peter',
        'last_name' => 'Doe',
    ]
];
$key = array_search(3245, array_column($records, 'id'));
echo $key;

edited Nov 4, 2019 at 17:42

answered Nov 4, 2019 at 17:07

Vladan

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2 Comments

rolinger Over a year ago

BRILLIANT! Thank you. I tested this and it works perfect. But what if the ID value isn't found - what does it return? I tested and $key was blank - is that an empty "" value?

Vladan Over a year ago

If not found, it returns false

jspit · Accepted Answer · 2019-11-04 17:36:36Z

0

You can also use array_column() to create a new array with id as key. You have then all fields in direct access.

$arrWithIdAsKey = array_column($records, null, 'id');

echo "<pre>".var_export($arrWithIdAsKey,true)."</pre>";

Example Output:

array (
  2135 => 
  array (
    'id' => 2135,
    'first_name' => 'John',
    'last_name' => 'Doe',
  ),
  3245 => 
  array (
    'id' => 3245,
    'first_name' => 'Sally',
    'last_name' => 'Smith',
  ),
  5342 => 
  array (
    'id' => 5342,
    'first_name' => 'Jane',
    'last_name' => 'Jones',
  ),
  5623 => 
  array (
    'id' => 5623,
    'first_name' => 'Peter',
    'last_name' => 'Doe',
  ),
)

answered Nov 4, 2019 at 17:36

jspit

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