Preg_match using array?

Question

Correct usage is: /,,([,]+)?|^,|,$|\b,\b|\s,/

$comma[0] = '/,,([,]+)?/';  
            $comma[1] = '/^,/';     
            $comma[2] = '/,$/';
            $comma[3] = '/\b,\b/';  
            $comma[4] = '/\s,/';    

$analyst = preg_match($comma, $_POST['analyst']) 
    ? mysql_real_escape_string($_POST['analyst']) : NULL;

I am trying to detect commas from the users input, each regex is defined properly, but I do not understand why it isn't passing them into the if statement.

Edit:

if I change this:

$analyst = preg_match('test', $_POST['analyst']) 
    ? mysql_real_escape_string($_POST['analyst']) : NULL;

then it works, this makes no sense.

Try reading the documentation: php.net/preg_match -- of course it fails, it doesn't accept an array. Nothing odd or unexpected at all. — Erik
– Erik, Commented May 3, 2011 at 17:08
No, Orbling, people just don't bother to look at basic documentation :( — Erik
– Erik, Commented May 3, 2011 at 17:10
A helpful answer would have been try using the pipe. /,,([,]+)?|^,|,$|\b,\b|\s,|,/ — RD Ward
– RD Ward, Commented May 3, 2011 at 17:17
Just out of idle curiosity, what could you possibly be trying to match against that str_pos( $_POST['analyst'], ',' ) wouldn't suffice? — stevecomrie
– stevecomrie, Commented May 3, 2011 at 17:20

stevecomrie · Accepted Answer · 2011-05-03 17:07:01Z

4

preg_match() doesn't accept arrays as arguments, only strings.

int preg_match ( string $pattern , string $subject [, array &$matches [, int $flags = 0 [, int $offset = 0 ]]] )

http://php.net/manual/en/function.preg-match.php

answered May 3, 2011 at 17:07

stevecomrie

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2 Comments

RD Ward Over a year ago

Well there you go. I just assumed it did. That is freaking weird. Thanks

RD Ward Over a year ago

Although it didn't solve my problem, it allowed me to learn how to use the pipe.

Shakti Singh · Accepted Answer · 2011-05-03 17:07:42Z

1

preg_match accept first parameter as string and you are passing an array.

answered May 3, 2011 at 17:07

Shakti Singh

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2 Comments

RD Ward Over a year ago

Is there a technical reason for this? It seems like an oversight to me.

Shakti Singh Over a year ago

@Ryan: Take a look at posted link

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