pass functions with different number of parameters to another function C++

Question

Imagine a function func1 parameters of which are a function f and its arguments. Let there be two functions func2 and func3 which are supposed to be passed to func1 with the following definitions:

bool func2(int a, int b, float c){
    // does something with arguments and returns the boolean result
}

bool func3(int a, int b, float c, float d){
    // does something with arguments and returns the boolean result
}

I wonder how should I define func1 so that it can be compatible with both of these functions. Of course there is a turnaround and that is to pass a dummy parameter to func2 but this is not a good solution. I have read this post but it did not seem to be a compatible solution. Any ideas?

Edit:

This function is a C++ template which is meant to be equivalent to a python function like:

def func1(f, int a, int b, *args):
    if f(a, b, *args):
        # does something

stackoverflow.com/questions/14719911/… But this smells. Why do you need this? — user2956272
– user2956272, Commented Nov 9, 2019 at 6:43
@dyukha The point is I have to write some templates in C++ for some python function which handles this issue. in python, you can use a *args parameter for variable number of arguments to be passed to the function f in func1 and I need an equivalent definition in C++. — Athena
– Athena, Commented Nov 9, 2019 at 6:56
I believe that you have XY problem, and should edit your question and ask what you really want to do (namely, call python functions with variable number of parameters). First, your use-case probably eliminates any template-based solution (since they are compile-time entities). Second, this problem is probably very standard, and people would quickly answer it. — user2956272
– user2956272, Commented Nov 9, 2019 at 7:12

Evg · Accepted Answer · 2019-11-09 08:04:31Z

4

Variadic templates can help you. The simplest version:

template<class Fn, typename... Ts>
void func1(Fn fn, int a, int b, Ts... args) {
    if (fn(a, b, args...))
        ...
}

func1(func2, 1, 2, 3);
func1(func3, 1, 2, 3, 4);

answered Nov 9, 2019 at 8:04

Evg

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Comments

Rohit Walavalkar · Accepted Answer · 2019-11-09 06:59:41Z

1

I prefer a more readable code even if increases the number of lines one need to write.

Signature of func2 and func3 looks more of less similar. Hence you can make the func2 accept another default parameter like below

bool func2(int a, int b, float c, float d = 0){
    // does something with arguments and returns the boolean result
}

bool func3(int a, int b, float c, float d){
    // does something with arguments and returns the boolean result
}

Now declare a function pointer and pass it to func1

bool (*fp) (int a, int b, float c, float d);

void func1(fp *fp1);

Please note that C++ doesn't really like function pointers

answered Nov 9, 2019 at 6:59

Rohit Walavalkar

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Comments

Pickle Rick · Accepted Answer · 2019-11-09 08:07:25Z

1

Sounds like you want a variadic template. Something like this should be fine (on mobile so may be syntax errors).

template<typename TCallback, typename TArgs...>
void Func1(TCallback Evt, TArgs... Args)
{
    Evt(Args...);
}

void Func2(int Arg1, int Arg2) { }

Func1(Func2, 10, 100);

answered Nov 9, 2019 at 8:07

Pickle Rick

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Comments

Andrew · Accepted Answer · 2019-11-09 06:47:37Z

0

I'm not 100% certain but I believe you should be creating a templatized function. Something like this.

template<typename T>
void func1 (T x, T y) {
    //code
}

Theoretically you should be able to substitute x and y with the bool from your function or whatever other values. Essentially you're creating your own custom type.

I've linked a reference below. Hope this helps.

https://en.cppreference.com/w/cpp/language/function_template

answered Nov 9, 2019 at 6:47

Andrew

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