How do I return an array of objects that only contains a certain object in an array for Javascript?

Question

I have an array of object called actors:

const actors =  [{
   "name": "John Doe",
   "rating": 1234,
   "alternative_name": null,
   "objectID": "551486300"
},
{
   "name": "Jane Doe",
   "rating": 4321,
   "alternative_name": "Monica Anna Maria Bellucci",
   "objectID": "551486310"
}];

I specifically want to get the name and the ratings of the actors. I tried getting it by making a function called actorNameRating, but my code does not work.

const nameAndRating = function() {

    const actorName = nameAndRating.filter(name);
    return actorName;

    const actorRating = nameAndRating.filter(rating);
    return actorRating;
 };

You cannot return twice from a function. After first return the code below will not be executed. — The_ehT
– The_ehT, Commented Nov 12, 2019 at 5:42

Shubham Verma · Accepted Answer · 2019-11-12 07:25:03Z

1

You can do by map a function and return only name and rating:

const actors =  [{
   "name": "John Doe",
   "rating": 1234,
   "alternative_name": null,
   "objectID": "551486300"
},
{
   "name": "Jane Doe",
   "rating": 4321,
   "alternative_name": "Monica Anna Maria Bellucci",
   "objectID": "551486310"
}];

const nameAndRating = function() {

   return actors.map(actor => ({
     name : actor.name,
     rating : actor.rating 
   }))
 };

console.log(nameAndRating())

answered Nov 12, 2019 at 7:25

Shubham Verma

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Comments

Amado · Accepted Answer · 2019-11-12 07:20:46Z

1

any thing after the return will not be executed you can return both values as one string then separate it for example :

const nameAndRating = function() {
    const actorName = nameAndRating.filter(name);
    const actorRating = nameAndRating.filter(rating);
    return actorName+","+actorRating;
 };

or any other way you find better for you to use

answered Nov 12, 2019 at 7:20

Amado

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