How to Fix This ERROR "JSON parse error: Cannot deserialize instance of `java.lang.Integer` out of START_OBJECT

Question

I want to build simple REST service API save to database postgresql using spring boot java. when I want to insert data to database but show errors, How can I fix it this problem? JSON parse error: Cannot deserialize instance of int out of START_OBJECT token; nested exception is com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of int out of START_OBJECT token, please Help me...

Here is the Rest Service Code

@RestController
@RequestMapping("/")
public class GenerateKeyController {


@Autowired
private GenerateKeyRepository gkrepo;

//getAll
@RequestMapping("/getAll")
List<KeyEntity> getAll(){
    return gkrepo.getAll();
}

//insert key
@RequestMapping(path ="/savekey", method = RequestMethod.POST)
    String simpanKey(@RequestBody int company_id) {
    String encKey = null;


    if (gkrepo.getOne(company_id) != null) {
     return "error, company sudah memiliki key";    
    }


    //terus save
    KeyEntity objKeyEntity;

    objKeyEntity = new KeyEntity();
    objKeyEntity.setCompanyid(company_id);
    objKeyEntity.setKeyencrypted(encKey);
    objKeyEntity.setCreationdate(new Date());

    gkrepo.save(objKeyEntity);

        return encKey;

     }
   }

This is My Entity

@Entity
@Table(name= "tb_key")
public class KeyEntity {

@Id
private Integer companyid;
private Date creationdate;
private String keyencrypted;

public Integer getCompanyid() {
    return companyid;
}
public void setCompanyid(Integer companyid) {
    this.companyid = companyid;
}
public Date getCreationdate() {
    return creationdate;
}
public void setCreationdate(Date creationdate) {
    this.creationdate = creationdate;
}
public String getKeyencrypted() {
    return keyencrypted;
}
public void setKeyencrypted(String keyencrypted) {
    this.keyencrypted = keyencrypted;
}

}

This is my Error Messages:

   2019-11-14 09:34:42.402  WARN 6932 --- [io-20000-exec-5] .w.s.m.s.DefaultHandlerExceptionResolver : Resolved [org.springframework.http.converter.HttpMessageNotReadableException: JSON parse error: Cannot deserialize instance of `java.lang.Integer` out of START_OBJECT token; nested exception is com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of `java.lang.Integer` out of START_OBJECT token at [Source: (PushbackInputStream); line: 1, column: 4]]

What is this snippet doing @RequestBody int company_id? And what is the input that you are passing? — aksappy
– aksappy, Commented Nov 14, 2019 at 3:05
i want to create parameter with data type, how can i write this? — user8108863
– user8108863, Commented Nov 14, 2019 at 3:20
@RequestBody triggers an auto conversion and in your case it just fails. Change the int to KeyEntity or a mapper DTO and run this — aksappy
– aksappy, Commented Nov 14, 2019 at 3:23
if I change the int to KeyEntity, where i write parameter? @aksappy — user8108863
– user8108863, Commented Nov 14, 2019 at 3:28

Harshal Khachane · Accepted Answer · 2019-11-14 03:53:07Z

3

You should be using

String simpanKey(@RequestBody RequestPOJO request) {

Instead of

String simpanKey(@RequestBody int company_id) {

And then using request extract all the fields coming from POST HTTP body, where RequestPOJO can look like

class RequestPOJO {
    int company_id;
}

answered Nov 14, 2019 at 3:53

Harshal Khachane

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ASK · Accepted Answer · 2019-11-14 04:41:19Z

If you don't want to provide complete request body in the request, instead you can do it by providing the company_id as 'PATH VARIABLE' OR 'REQUEST PARAM'. e.g.

1.Using PathVariable

@RequestMapping(path ="/savekey/{company_id}", method = RequestMethod.POST)
String simpanKey(@PathVariable int company_id) {

// your predefined logic
// now it will be provided in the url without any request body

}

In this case, your url will be :
**http://111.111.1.111:0000/savekey/1**

2.Using RequestParam :

@RequestMapping(path ="/savekey", method = RequestMethod.POST)
String simpanKey(@RequestParam int company_id) {

 // your predefined logic
 // now it will be provided in the url without any request body

}

In this case, your url will be :
**http://111.111.1.111:0000/savekey?company_id=1**

Hope, you can consider or try these as well.

Noumenon · Accepted Answer · 2020-05-06 14:13:59Z

0

If your JSON comes from Postman, you get this error when you try to send in a variable without quotes:

{ "key": {{myIntVariable}} }

instead of

{ "key": "{{myIntVariable}}" }

Even numbers need to be wrapped with quotes this way.

answered May 6, 2020 at 14:13

Noumenon

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