2

I have a one dimensional numpy array, for example looking like :

[500.774994, 2837.050049, 492.190002, 2840.379883, 475.800018, 2828.725098]

Assuming the size of the array is a multiple of 2, how could i convert it into an array of pairs of the following shape ?

[(500.774994, 2837.050049), (492.190002, 2840.379883), (475.800018, 2828.725098)]

or

[[500.774994, 2837.050049], [492.190002, 2840.379883], [475.800018, 2828.725098]]

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2 Answers 2

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5

You just need a reshape:

a = np.array([500.774994, 2837.050049, 492.190002, 2840.379883, 475.800018, 2828.725098])

a.reshape(-1, 2)

array([[ 500.774994, 2837.050049],
       [ 492.190002, 2840.379883],
       [ 475.800018, 2828.725098]])
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Comments

1

Try this:

x = [500.774994, 2837.050049, 492.190002, 2840.379883, 475.800018, 2828.725098]
list(zip(x[::2],x[1:]))

Output:

[(500.774994, 2837.050049),
 (492.190002, 492.190002),
 (475.800018, 2840.379883)]
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4 Comments

Maybe check if len(x) may be divided by two? Just for safety...
No need since zip does not require 2 arrays to have same length
it works, thanks @ExplodingGayFish ! (what a crazy name ^^).
@MartinSteinborn dont worry i already handle this case, and to focus only on the transformation matter i specified we were assuming it was dividable by 2 in the post :) .

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