I have two examples one I have a group of functions like this:
const funcs = () => {
const foo = (t: string) => `${t} meow`
const bar = (t: string) => `${t} woof`
return { foo, bar }
}
The other is just a stand alone function:
const foo = (t: string) => `${t} meow`
How can I add these to an existing class:
class Example {
}
I'm open to decorators, ideally I don't have to open up the constructor.
I think that you would be able to add those methods at the run time by adding it to the prototype of Example
const funcs = () => {
const foo = (t: string) => `${t} meow`
const bar = (t: string) => `${t} woof`
return { foo, bar }
};
class Example {
[prop: string]: any;
}
let fns:{[prop: string]: any;} = funcs();
for (let key of Object.keys(fns)) {
let fn = fns[key];
Example.prototype[key] = fn;
}
console.log(new Example().bar("hello"));
The crux for this way is that these methods are added at runtime. So, the typescript compiler doesn't know they even exist in example's prototype.
I think that this isn't something we shoud do if we're using typescript because typescript's sole purpose is to check stuff at compile time.
I believe the best way is to refractor it if you're using typescript.
bar = foo;like typescriptlang.org/play/….