I am relatively a noobie in programming and trying to learn python. I was trying to implement a Fibonacci series into a list within 10.
fibo= [0,1]
for k in range(11):
i= fibo[-1]
j = fibo[-2]
k= fibo[i]+fibo[j]
fibo.append(k)
k=+1
print(fibo)
Not sure what I did wrong? Any help is really appreciated!
Output:
[0, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2]
You can use this code to print fibonacci series upto N.
N = int(input()) # Length of fibonacci series
fibo = [0, 1]
a = fibo[0]
b = fibo[1]
for each in range(2, N):
c = a + b
a, b = b, c
fibo.append(c)
print(fibo[:N])
OUTPUT
N = 10
[0, 1, 1, 2, 3, 5, 8, 13, 21, 34]
I can see few issues here:
fibo = [0,1]
# Your loop should start at index 2, otherwise
# you will try to access fibo[-2] and fibo[-1] with k=0
# and fibo[-1] and fibo[0] with k=1
# Also, if you only want 10 values, you should change 11
# to 10 since fibo already has two values.
# for k in range(11):
for k in range(2, 10):
# You don't want the content of fibo, but the indexes!
# i = fibo[-1]
# j = fibo[-2]
i = k - 1
j = k - 2
# You are already using k, so you need to use an other variable
# k = fibo[i] + fibo[j]
v = fibo[i] + fibo[j]
fibo.append(v)
# You don't need k+=1 because it will be incremented
# according to range(2, 10). The loop will start with
# k = 2 and it will stop when k = 9
# k += 1
print(fibo)
Your code did not crash because you technically can access fibo[-1] and fibo[-2]. It will respectively return the last value of your array, and the value before the last one.
