I have a string pattern:
"(https?://finance\.sina\.com\.cn/.+?shtml)"
and I use findall method of re to match a content, but the result contains:
'http://finance.sina.com.cn/nmetal/" target="_blank" style="margin-right:7px">黄金</a><a href="http://finance.sina.com.cn/futures/quotes/CL.shtml'
and I have used non-greedy operators, but it still get wrong, where am I wrong?
Your problem is that the first part of your regex:
https?://finance\.sina\.com\.cn/
matches the URL in the first <a> tag, and the second part
.+?shtml
then matches until it sees the .sthml in the second <a> tag because there is no .shtml on the first href. Ideally you should be using a DOM parser to parse HTML; then you couldn't run into this problem. In the interim, changing .+? into [^"]+ so that part of the regex cannot go past the end of the current href will solve your problem. i.e.
(https?://finance\.sina\.com\.cn/[^'"]+shtml)
a = "http://finance.sina.com.cn/money/gold/AUTD/quote.shtml',name: '黄金',symbol: 'hf_AUTD',type: 'hf' },\n\t\t\t\t\t\t\t{ link: 'http://finance.sina.com.cn/money/gold/AGTD/quote.shtml'" b = re.findall('(https?://finance\.sina\.com\.cn/[^"]+shtml)', a) print(b), , it still has wrong.