using Regular exprestion to validate IP Address in Powershell?

Question

I have this code in PowerShell and it does not work! any help?

I just need it to make sure that the string is a working IP not 999.999.999.999 or a normal string

just an IP [0....255].[0....255].[0....255].[0....255]

if ($newIP -match "(\b(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.(25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b)") { $x = $True}

cheers

you can find a ton of matches for IP address by googling or directly here at stackoverflow. See here for the formal matching (called also complex beast :) — Emiliano Poggi
– Emiliano Poggi, Commented May 5, 2011 at 17:45

mjolinor · Accepted Answer · 2012-04-15 14:51:49Z

29

How about:

[bool]($newIP -as [ipaddress])

edited Apr 15, 2012 at 14:51

user142162

answered May 5, 2011 at 17:21

mjolinor

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1 Comment

David Klempfner Over a year ago

This doesn't work all the time. If you put in "10.10" for example, it will say it's a valid IPAddress because the it will convert it to "10.0.0.10". See stackoverflow.com/questions/39988644/… for more info

mousio · Accepted Answer · 2011-05-05 16:29:52Z

1

Here is a more compact one:

\b(([01]?\d?\d|2[0-4]\d|25[0-5])\.){3}([01]?\d?\d|2[0-4]\d|25[0-5])\b

answered May 5, 2011 at 16:29

mousio

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1 Comment

Tanaka Saito Over a year ago

For those stumbling onto this thread now 11 years later: this solution is not correct as the expression will evaluate 0.0.0.0 as a valid IP address which it is not. The problem is the \d which allows zeros.

smottt · Accepted Answer · 2015-03-16 14:29:38Z

0

or even shorter

^(?:[0-9]{1,3}\.){3}[0-9]{1,3}$

edited Mar 16, 2015 at 14:29

smottt

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answered Mar 16, 2015 at 11:25

Nin Kan

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2 Comments

Alexander Sinno Over a year ago

I wanted to add that I have been using this IPRegex and have tested it against hundreds of IP addresses. It works like a charm.

Joseph Over a year ago

What? That's basically saying it accepts any combination of 1 to 3 digits and has a period between them...

Zoe - Save the data dump · Accepted Answer · 2018-06-11 08:07:07Z

0

This works fine and errors if not full IP

$Name = "1.1" ; [bool]($Name -as [ipaddress] -and ($Name.ToCharArray() | ?{$_ -eq "."}).count -eq 3)

edited Jun 11, 2018 at 8:07

Zoe - Save the data dump

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answered Jun 11, 2018 at 8:03

Colin

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2 Comments

Yunnosch Over a year ago

Welcome to StackOverflow Colin. However, if this is an answer to the question (I am not sure) then it requires a little rephrasing of the explanation for clarity and readability and maybe a little formatting of the shown code.

Yunnosch Over a year ago

Please take the tour at your convenience.

Ivo Ivanov · Accepted Answer · 2017-01-20 14:47:22Z

-2

The following will not work ^(?:[0-9]{1,3}.){3}[0-9]{1,3}$ Take for example the part that needs to match the last octet from the IP Address [0-9]{1,3} - This will not match only number in the interval 0 to 255 Your best approach will be to dived checking of a single octet to 250 to 255; 240 to 249; 100 to 199; 10 to 99; and 0 to 99.

answered Jan 20, 2017 at 14:47

Ivo Ivanov

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1 Comment

pen2 Over a year ago

There is no word in main question that ^(?:[0-9]{1,3}.){3}[0-9]{1,3}$ should work. Instead of writing what will not work please try to write what will with some proper examples.

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