How to get required text from a string using python?

Question

I have a multiline string from which I need to split and get only required texts. I should not count the index manually because the length might change every time.

My Python code

test= "all:qwe:ew1:aq-nps-3:977232323342:isc/isc-04987s4c12399a1sa"
a= test.split()
print(a)

Now I am stuck here on how to proceed further.

I want to get "aq-nps-3" and "isc-04987s4c12399a1sa" values alone from a string and store it in different variable. Can anyone guide me on further steps? Is it a good way to count index manually or how I can get these required values alone.

Expected results:

a= aq-nps-3
b= isc-04987s4c12399a1sa

You need to define a rules of what makes your "required texts" as required — RomanPerekhrest
– RomanPerekhrest, Commented Nov 27, 2019 at 10:35
I agree with @RomanPerekhrest, Why you need that thing only, Are there any patters for it or identity to extract the text? — Juhil Somaiya
– Juhil Somaiya, Commented Nov 27, 2019 at 10:38
yes I need that particular texts only for my future validation purpose — Mia
– Mia, Commented Nov 27, 2019 at 10:40
what if the statement changes to something else? I suggest to make a generic patter instead of just extracting from the string.! — Juhil Somaiya
– Juhil Somaiya, Commented Nov 27, 2019 at 10:42

Jordan Dimov · Accepted Answer · 2019-11-27 10:37:45Z

2

Looks like you should be splitting by the : character:

 bits = test.split(':')
 a = bits[3]
 b = bits[5]
 print(a, b)

answered Nov 27, 2019 at 10:37

Jordan Dimov

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Mia · Accepted Answer · 2019-11-27 11:55:52Z

0

I was able to crack with below code,

test= "all:qwe:ew1:aq-nps-3:977232323342:isc/isc-04987s4c12399a1sa"
a= (test.split(':')[-1]).split('/')[-1]
print(a)

answered Nov 27, 2019 at 11:55

Mia

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