I have been trying to iterate through an array.
below is the code.
x = ['lemon', 'tea', 'water', ]
def randomShuffle (arr,n):
from random import choices
newList=[]
for item in arr:
r=choices(arr, k=n)
if r.count(item) <= 2:
newList.append(item)
return (newList)
i would like to know the logic for writing it please.
thank you all
Use a while loop: if every item is to appear twice, then teh resulting array should be twice the length of the input one.
And of course check not to add the same item more than twice in the result ;)
Choices return a list of size 1, so I use [0] to get the element
xx = ["a", "b", "c"]
def my_function(x):
res = []
while len(res) < len(x) * 2:
c = choices(x)[0]
if res.count(c) < 2:
res.append(c)
return res
my_function(xx)
> ['c', 'c', 'a', 'b', 'a', 'b']
my_function(xx)
> ['a', 'b', 'b', 'a', 'c', 'c']
