I want to search 3 Words in a String and put them in a List something like:
sentence = "Tom once got a bike which he had left outside in the rain so it got rusty"
pattern = ['had', 'which', 'got' ]
and the answer should look like:
['got', 'which','had','got']
I haven't found a way to use re.finditer in such a way. Sadly im required to use finditer
rather that findall
You can build the pattern from your list of searched words, then build your output list with a list comprehension from the matches returned by finditer:
import re
sentence = "Tom once got a bike which he had left outside in the rain so it got rusty"
pattern = ['had', 'which', 'got' ]
regex = re.compile(r'\b(' + '|'.join(pattern) + r')\b')
# the regex will be r'\b(had|which|got)\b'
out = [m.group() for m in regex.finditer(sentence)]
print(out)
# ['got', 'which', 'had', 'got']
The idea is to combine the entries of the pattern list to form a regular expression with ors. Then, you can use the following code fragment:
import re
sentence = 'Tom once got a bike which he had left outside in the rain so it got rusty. ' \
'Luckily, Margot and Chad saved money for him to buy a new one.'
pattern = ['had', 'which', 'got']
regex = re.compile(r'\b({})\b'.format('|'.join(pattern)))
# regex = re.compile(r'\b(had|which|got)\b')
results = [match.group(1) for match in regex.finditer(sentence)]
print(results)
The result is ['got', 'which', 'had', 'got'].
