$string = "Hello World Again".
echo strrchr($string , ' '); // Gets ' Again'
Now I want to get "Hello World" from the $string [The substring before the last occurrence of a space ' ' ]. How do I get it??
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11 Answers
$string = "Hello World Again";
echo substr($string, 0, strrpos( $string, ' ') ); //Hello World
If the character isn't found, nothing is echoed
Comments
This is kind of a cheap way to do it, but you could split, pop, and then join to get it done:
$string = 'Hello World Again';
$string = explode(' ', $string);
array_pop($string);
$string = implode(' ', $string);
One (nice and chilled out) way:
$string = "Hello World Again";
$t1=explode(' ',$string);
array_pop($t1);
$t2=implode(' ',$t1);
print_r($t2);
Other (more tricky) ways:
$result = preg_replace('~\s+\S+$~', '', $string);
or
$result = implode(" ", array_slice(str_word_count($string, 1), 0, -1));
8 Comments
zaf
@sdleihssirhc thanks for writing that comment because otherwise people would now not know who was the fastest kid here. thats right, vote for me people.
zaf
@locrizak dude, 3 operations not 4.
zaf
@locrizak check the 1 operation kung fu and weep.
andrewtweber
Just because something is written in one line does not make it one operation. The preg_replace is one operation but is specific to whitespace (the question asked about any character).
andrewtweber
@Yehonatan Read the damn question title. "last occurrence of a character"
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strripos — Find the position of the last occurrence of a case-insensitive substring in a string
$string = "hello world again";
echo substr($string, 0, strripos($string, ' ')); // Hello world
1 Comment
Oleg Estekhin
Essentially the same code as in @Till answer, and without any explanation too.
$myString = "Hello World Again";
echo substr($myString, 0, strrpos($myString, " "));
Comments
The correct implementation should be:
$string = "Hello World Again";
$pos = strrpos( $string, ' ');
if ($pos !== false) {
echo substr($string, 0, $pos ); //Hello World
}
Otherwise if the character is not found it will print nothing. See following case:
$string = "Hello World Again";
//prints nothing as : is not found and strrpos returns false.
echo substr($string, 0, strrpos( $string, ':') );
Comments
The most direct, single-function approach is to use preg_replace() to remove the last space and all remaining characters (which logically cannot include any spaces).
This is suitable for a wide range of textual scenarios and is easy to adjust because there are just 3 basic components in the pattern.
- match a space
[^ ]* - match zero or more non-space characters
$ - match the end of the string
If there are no spaces in the input string, then the input string will remain unchanged.
Code: (Demo)
$string = "Hello World Again";
var_export(preg_replace('/ [^ ]*$/', '', $string));
// 'Hello World'
3 Comments
rozsazoltan
Underappreciated answer. Is it similar in performance to the top answer?
mickmackusa
On a single string, no human will ever notice any difference either way. On several hundred thousands of strings, I don't know which way will be faster and I am not motivated to benchmark it to be honest. I prefer this way on the grounds of directness/brevity.
rozsazoltan
Yeah, what caught my attention was its brevity. I usually avoid regex solutions, but I like this one.
You could just use:
$string = "Hello World Again";
echo preg_replace('# [^ ]*$', '', $string);
This will work regardless of whether the character occurs in the string or not. It will also work if the last character is a space.
2 Comments
s1x
Dont forget the # as a delimiter!
mickmackusa
This would actually be the approach I would use ...if the code was valid. :(
function cutTo($string, $symbol) {
return substr($string, 0, strpos($string, $symbol));
}
Comments
<?php
$str = "Hello World!";
echo $str . "<br>";
echo chop($str,"World!");
// output - Hello
?>
