How can I detect if a string ends with values inside an array?
array('.1.jpg','.2.jpg','.3.jpg','.4.jpg','.5.jpg','.6.jpg','.7.jpg','.8.jpg','.9.jpg');
the string can be: image.1.jpg or it can be image.11.jpg
But I need to find only if string ends with one the values inside the array.
If you need to use all periods in the string, then just get everything from the first period to the end and see if it is in the array:
if(in_array(strstr($string, '.'), $array)) {
//yes
}
Obviously something like my.image.1.jpg would fail as it would look for .image.1.jpg.
A good-old solution, which gives you as well the found index in the array:
function endsBy(string $str, array $arr): ?int
{
$len = strlen($str);
foreach ($arr as $i => $toTest) {
$toTestLen = strlen($toTest);
if ($toTestLen <= $len && substr_compare($str, $toTest, $len - $toTestLen) === 0) {
return $i;
}
}
return null;
}
To use it as described in your question:
if (endsBy($myString, $array) !== null) {
...
}
if (in_array(substr($string, -6), $array)) {
//yes
}
As all your examples have the exact same length. No REGEX or replacement required.
-6 is the part that breaks this answer (makes it incorrect/unsuitable).I had a similar situation. In my case, I wanted to test if a filename ended with one of the given extensions. The allowedExtensions could be passed into a function or defined as a constant. It may also change in the future.
I went with something like this:
const allowedExtensions = ['.docx', '.jpg', '.txt', '.csv'];
const isAllowed = allowedExtensions.some((ext) => filename.endsWith(ext));
preg_match('/\.[1-9]\.jpg$/', $string)