How to extract Version number from the web content using preg_match php

Question

I would like to extract the version number from the url content. i tried to extract info using curl_exec. but unable to get the preg_match to get the exact info.

Code i tried is

function getVersionFromurl(string $url)
{
    $curl = curl_init($url);
    $content = curl_exec($curl);
    curl_close($curl);
    $rx = preg_match("(\"version\" (\d+\.\d+\.\d+\.\d+))", $content, $matches);
    echo $matches[1];
}

$url = 'https://www.foxitsoftware.com/downloads/downloadForm.php?retJson=1&product=Foxit-Reader&platform=Mac-OS-X';
$val = getVersionFromurl($url);

here the content came as

"{"package_info":{"language":["English","French","German","Italian","Spanish"],"type":["pkg"],"version":["3.4.0.1012","2.1.0804","2.0.0625","1.1.1.0301","1.1.0.0128"],"size":"139.13MB","release":"10/15/19","os":"","down":"/pub/foxit/reader/desktop/mac/3.x/3.4/ML/FoxitReader340.setup.pkg","mirror":"","manual":"","big_version":"3.x"}}1"

How to extract 3.4.0.1012 from the content. the preg_matcxh i tried gives me error. how to write the preg_match regular expression.

Please any help.

Your pattern could look like "version":\["(\d+(?:\.\d+){3})" See regex101.com/r/wen7ya/1 — The fourth bird
– The fourth bird, Commented Dec 29, 2019 at 10:47

XPS · Accepted Answer · 2019-12-29 10:34:41Z

3

better to convert string to JSON object, and get version value from there

function getVersionFromurl(string $url)
{
    $curl = curl_init($url);
    $content = curl_exec($curl);
    curl_close($curl);

    $contentObj = json_decode($content);
    echo $contentObj.package_info.version[0];
}

$url = 'https://www.foxitsoftware.com/downloads/downloadForm.php?retJson=1&product=Foxit-Reader&platform=Mac-OS-X';
$val = getVersionFromurl($url);

Notice this conversion from string into object, and get first element of version array

$contentObj = json_decode($content);
echo $contentObj.package_info.version[0];

edited Dec 29, 2019 at 10:34

answered Dec 29, 2019 at 10:29

XPS

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Comments

The fourth bird · Accepted Answer · 2019-12-29 10:58:32Z

1

In your pattern you are not accounting for this part :\[" after "version" You are also using 2 capturing groups, so $matches[1] would then contain the whole match and $matches[2] would contain your value.

But instead, you can use 1 capturing group.

"version":\["(\d+(?:\.\d+){3})"

Regex demo | Php demo

preg_match('~"version":\["(\d+(?:\.\d+){3})"~', $content, $matches);
echo $matches[1];

Output

3.4.0.1012

Note that you don't have to escape the double quotes and that you have to use delimiters for the pattern.

answered Dec 29, 2019 at 10:58

The fourth bird

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2 Comments

surendra Over a year ago

i get the error 'PHP Notice: Undefined offset: 1 in /workspace/Main.php on line 8" . for "echo $matches[1];" it looks like preg_match returned nothing.

The fourth bird Over a year ago

Are you sure you have the same payload? What does the string look like?

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