I am new to ajax and was following a youtube tutorial to create a simple food search app where users enter food name in input field it shows the name below else it says that food not available but somehow its not working on wamp server ..it shows the error alert instead
here is my code
index.html
<!Doctype html>
<html lang = "en">
<head>
<title>Ajax app</title>
<meta charset = "UTF-8">
<style>
</style>
<script type="text/javascript" src="foodstore.js"></script>
</head>
<body onload="process()">
<h3>The Chuff Bucket</h3>
Enter the food you would like to order:
<input type="text" id="userInput"/>
<div id="underInput"></div>
</body>
</html>
foodstore.js
var xmlHttp = createXmlHttprequestObject();
function createXmlHttprequestObject()
{
var xmlHttp;
if(window.ActiveXObject){
try{
xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");
}catch(e){
xmlHttp =false;
}
}else{
try{
xmlHttp = new XMLHttpRequest();
}catch(e){
xmlHttp =false;
}
}
if(!xmlHttp){
alert("can't create that object boss");
}else{
return xmlHttp;
}
}
function process()
{
if(xmlHttp.readyState==0||xmlHttp.readyState==4){
food = encodeURIComponent(document.getElementById("userInput").value);
xmlHttp.open("GET","foodstore.php?food=" + food, true);
xmlHttp.onreadystatechange = handleServerResponse;
xmlHttp.send(null);
}else{
setTimeout("process()",1000);
}
}
function handleServerResponse()
{
//readystate 4 whenever response is ready and object done communicating
if(xmlHttp.readyState==4){
//state 200 means communiaction went ok
if(xmlHttp.readyState==200){
xmlResponse = xmlHttp.responseXML;
xmlDocumentElement = xmlResponse.documentElement;
message = xmlDocumentElement.firstChild.data;
document.getElementById("underInput").innerHTML = "<span style='color:blue'>" + message + "</span>"
setTimeout("process()",1000);
}else{
alert("something went wrong");
}
}
}
foodstore.php
<?php
header("Content-type: text/xml");
echo "<?xml version='1.0' encoding='UTF-8' standalone='yes'?>";
echo "<response>";
$food = $_GET["food"];
$foodArray = array("tuna","bacon","beef","loaf","ham");
if(in_array($food,$foodArray))
{
echo "We do have" .$food. "!";
}
elseif($food ="")
{
echo "Enter a food please.";
}
else
{
echo"sorry but we don't even sell" . $food. "!";
}
echo "</response>";
?>
any help will be highly appreciated ,thanks
200 okstatus code, you need to check what is the response in your browser network tab.