Symfony Always Include Route Default Values

Question

So basically I am trying to achieve this: New in Symfony 4.3: Always Include Route Default Values

I have a task entity, which has multiple states like new, open & closed.

For this reason I am trying to generate a route /tasks/new /tasks/open /tasks/closed. However, if there is no option set in my route, I want it to use new as default and also add it to the url.

My controller:

/**
 * @Route("/tasks/{!status?new}", name="app_tasks")
 */
public function tasks(TaskRepository $taskRepository, string $status)
{
    $tasks = $taskRepository->findBy(['status' => $status]);
    return $this->render('tasks/index.html.twig', ['tasks' => $tasks]);
}

However this results into not a single matching route.

/tasks/new  => no route found  => should work
/tasks/open => no route found  => should work
/tasks      => no route found  => should work & route should be /tasks/new
etc.

The main issue seems to be the ! before status. If I remove it entirely, everything works as expected, except that the route for new tasks looks like /tasks and not like /tasks/new - what I actually want.

I already tried to clear my cache - not working though. Symfony version is 4.4.2.

Haiberd · Accepted Answer · 2020-01-07 15:11:38Z

2

+50

There is an open issue on github. This will likely be fixed in newer releases.

As for now try using the following:

@Route("/tasks/{!status}", name="app_tasks", defaults={"status": "new"})

answered Jan 7, 2020 at 15:11

Haiberd

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yivi · Accepted Answer · 2020-01-07 14:50:57Z

-2

Perhaps you can use 2 routes for the same method. One with the slug, one by default if not caught.

Or you can check with a basic if in the controller depending on the slug of your main issues .

edited Jan 7, 2020 at 14:50

yivi

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answered Jan 6, 2020 at 14:39

A.DREY

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