Use parameters in function after interrupt signal [duplicate]

Question

Is it possisble in bash script to use parameters in a function, which is called after interrupt signal? Here's my code:

    inCaseOfInterrupt ()
    {
        while [ $# -gt 0 ]
        do
                echo "$1"
                shift
        done
        exit 0
    }

And in the other part of my script I have:

trap inCaseOfInterrupt 2

But it doesn't recognize my parameters. How can I use parameters in a function after script gets interrupt signal?

John Kugelman · Accepted Answer · 2020-01-08 18:10:17Z

0

trap 'inCaseOfInterrupt 2' 2

Or, with a signal name:

trap 'inCaseOfInterrupt 2' INT

answered Jan 8, 2020 at 18:10

John Kugelman

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3 Comments

Sa1m0n Over a year ago

Thank you, but when I pass parameters: "test1 test2 test3", I get "2" on the output instead of "test1 test2 test3", which I expected.

John Kugelman Over a year ago

Pass parameters how?

Sa1m0n Over a year ago

When I run my script in Bash shell: ./myScript test1 test2 test3

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