Extract specific data from string using Regex (PHP)

Question

My objective is to check if the message have emojis or not , if yes i am going to convert them. I am having a problem to find out how many emojis are in the string.

Example :

$string = ":+1::+1::+1:"; //can be any string that has :something: between ::

the objective here is to get the :+1: ( all of them ) but i tried two pattern and i keep getting only 1 match.

preg_match_all('/:(.*?):/', $string, $emojis, PREG_SET_ORDER); // $emojis is declared as $emojis='' at the beginning.
preg_match_all('/:(\S+):/', $string, $emojis, PREG_SET_ORDER);

The Rest of the code
after getting the matches i am doing this :

 if (isset($emojis[0])) 
   {
        $stringMap = file_get_contents("/api/common/emoji-map.json");
        $jsonMap = json_decode($stringMap, true);

        foreach ($emojis as $key => $value) {
            $emojiColon = $value[0];
            $emoji = key_exists($emojiColon, $jsonMap) ? $jsonMap[$emojiColon] : '';
            $newBody = str_replace($emojiColon, $emoji, $newBody);
        }
   }

i would appreciate any help or suggestions , Thanks.

i tried that in different cases but i still have some problems , i'll test more tho , thank you — Mohamed Ali Nakouri
– Mohamed Ali Nakouri, Commented Jan 16, 2020 at 19:25

Nippey · Accepted Answer · 2020-01-17 08:10:41Z

1

I updated your expression a little bit:

preg_match_all('/\:(.+?)(\:)/', $string, $emojis, PREG_SET_ORDER);
echo var_dump($emojis);

The : is now escaped, otherwise it could be treated as special character.
Replaced the * by +, this way you won't match two consecutive :: but require at least one charcter in-between.

edited Jan 17, 2020 at 8:10

Nippey

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answered Jan 17, 2020 at 0:14

bulletvz

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1 Comment

Nippey Over a year ago

Hello bulletvz, welcome to Stackoverflow! Your answer has been flagged because of its short length. For better readable answers next time, please take your time and provide a short comment of what you did to fix the issue.

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