I would like to run multiple command inside a for loop that will contain two arrays. In other words, I need to have a nested for loop that will execute the commands with the following process:
echo one
echo 8df6
echo two
echo b4c2
echo three
echo 9fad
below is some code that tried, but couldn't apply what needed.
#!/bin/bash
numbers=(one two three)
numbersid=(8df6 b4c2 9fad)
for m in "${numbers[@]}"
do
echo "${m}";
for n in "${numbersid[@]}"
do
echo "${n}" ;
done
done;
thank you.
in this case a single loop would suffice:
#!/bin/bash
numbers=(one two three)
numbersid=(8df6 b4c2 9fad)
for index in 0 1 2
do
echo ${numbers[$index]}
echo ${numbersid[$index]}
done
gives:
one
8df6
two
b4c2
three
9fad
Note that bash can help you extract the indices of an array:
#...............v
for index in "${!numbers[@]}"; do
echo ${numbers[index]}
echo ${numbersid[index]}
done
seq; if you are using bash, then a C-style for loop is simpler and more efficient: for ((index=0; index < ${#numbers[@]}; index++)). If you need POSIX compatibility, you can't rely on seq being available anyway, so you should use a while loop that explicitly manages index.If you check the output for your code, you would notice that having 2 for loops inside each other results in running the nested for loop every iteration of the first for loop.
Therefore, after every number you will have all the numberids print.
Your goal is to print both the number and the numberid after each other. So you want to iterate over the length of the number array. And then print the number, and its id.
You can achieve that in the following way.
#!/bin/bash
numbers=(one two three)
numbersid=(8df6 b4c2 9fad)
for i in "${!numbers[@]}"
do
echo "${numbers[i]}";
echo "${numbersid[i]}";
done;
