Start from the beginning using while loop on connection times out using Selenium and Python

Question

from selenium import webdriver
import time

browser = webdriver.Chrome('C:/Users/acer/Desktop/chromedriver')
browser.get('website')

def user():
    while True:
        time.sleep(1)
        try:
            browser.find_element_by_id('q').send_keys('name') #Type in name
            browser.find_element_by_tag_name('button').click()  #Click "verify"

        finally:
            browser.find_element_by_tag_name('button').click()  #When connection times out, click "try again"
user()      #When connection times out again run "while loop" from the begining

I want to start from the beginning when the connection times out again and make a never ending loop until connection is successful.

undetected Selenium · Accepted Answer · 2020-01-19 21:11:21Z

Seems you were near perfect. To demonstrate "to start from the beginning when the connection times out again and make a never ending loop until connection is successful" here is a small program which does the following:

Opens the url https://www.google.com/
Finds out the element By.NAME, "q"
Clears the field
Sends the character sequence name
Attempts to click on the element find_element_by_tag_name('button')
Fails and using continue keeps on retrying.

Code Block:

from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException, WebDriverException

options = webdriver.ChromeOptions() 
options.add_argument("start-maximized")
options.add_experimental_option("excludeSwitches", ["enable-automation"])
options.add_experimental_option('useAutomationExtension', False)
browser = webdriver.Chrome(options=options, executable_path=r'C:\WebDrivers\chromedriver.exe')
browser.get('https://www.google.com/')
def user():
    while True:
        print("Starting while loop")
        try:
            element = WebDriverWait(browser, 20).until(EC.element_to_be_clickable((By.NAME, "q")))
            element.clear() #clear the previous text
            element.send_keys('name') #Type in name
            browser.find_element_by_tag_name('button').click()
        except (WebDriverException, TimeoutException):
            print("Go to while loop from the begining")
            continue
user()

Console Output:

Starting while loop
Go to while loop from the begining
Starting while loop
Go to while loop from the begining
Starting while loop
Go to while loop from the begining
.
.
.

This usecase

You can follow similar logic and your effective code block will be:

from selenium import webdriver
import time

browser = webdriver.Chrome('C:/Users/acer/Desktop/chromedriver')
browser.get('website')

def user():
    while True:
    time.sleep(1)
    try:
        browser.find_element_by_id('q').send_keys('name') #Type in name
        browser.find_element_by_tag_name('button').click()  #Click "verify"

    except WebDriverException:
        continue #When connection times out again run "while loop" from the begining
user()

Sam Broster · Accepted Answer · 2020-01-19 15:05:14Z

1

So you're almost there. You need to use try/except rather than try/finally.

Selenium will raise a timeout exception. except and finally are both used to when dealing with exceptions:

except when python raises an exception the program will exit unless you catch the exception using an except branch
finally if an exception is raised, any code in the finally branch is executed before the program exits.

If you use an except branch then the program will just loop around again. Make sure that you catch the specific timeout exception in the except branch otherwise your program will slow all errors!

answered Jan 19, 2020 at 15:05

Sam Broster

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