Got an ArrayD which always has 2 dimensions, but is an ArrayD due to a calculation, need to change this to Array2 for storage.
Been looking through documentation, can't seem to find a way.
Is there a function to do it?
asked Jan 19, 2020 at 20:43
Jonathan Woollett-light
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It looks like your question might be answered by the answers of How to convert a collection of Vec<ndarray::Array1> into an Array2?. If not, please edit your question to explain the differences. Otherwise, we can mark this question as already answered.Shepmaster– Shepmaster2020-01-20 13:21:11 +00:00Commented Jan 20, 2020 at 13:21
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@Shepmaster This does not answer my question, the answer basically recommends iterating through every element and just copying them. This could be said of almost any data structure and I would presume the inference could be made I am looking for some reasonably efficient cast, not simply looping through every value (which is what I am doing already).Jonathan Woollett-light– Jonathan Woollett-light2020-01-20 14:47:26 +00:00Commented Jan 20, 2020 at 14:47
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1 Answer
If you have a variable of type ArrayD<f32>, you can do:
// convert n-dimensional array into 2d array
let arr2d: Array2<f32> = arr2d.into_dimensionality::<Ix2>()?;
to convert it into a variable of type Array2<f32>.
If the dimensions don't match, it will throw an ndarray::ShapeError error.
