Include For loop inside function for processing list of tuples

Question

I have a function to process the list of tuples. What is the easiest way to include for loop inside the function itself? I am fairly new to python, trying to convert this in OOP function. Any help will be appreciated.

My current solution:

tups = [(1,a),(2,b),(5,t)]

def func(a,b):
    # do something for a and b
    return (c,d)

output = []
for x, y in tups:
    output.append(func(x,y))

output will be

[(c,d),(m,n),(h,j)]

stackoverflow.com/questions/1663807/… stackoverflow.com/questions/8372399/… stackoverflow.com/questions/10867882/… — user10063119
– user10063119, Commented Jan 22, 2020 at 4:22
What is the issue, exactly? What is the easiest way to include for loop inside the function itself? Are you asking how to write a for loop? — AMC
– AMC, Commented Jan 22, 2020 at 4:29

Sociopath · Accepted Answer · 2020-01-22 04:57:03Z

1

I think map is more suitable for your use case

tups = [(1,"a"),(2,"b"),(5,"t")]

def func(z):
    # some random operation say interchanging elements
    x, y = z
    return y, x

tups_new = list(map(func, tups))
print(tups_new)

Output:

[('a', 1), ('b', 2), ('t', 5)]

answered Jan 22, 2020 at 4:57

Sociopath

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1 Comment

MikeCode Over a year ago

This was quick and easy. Thanks!

score 1 · Accepted Answer · 2020-02-03 16:53:13Z

1

just write your loop in func:

tups = [(1,a),(2,b),(5,t)]

def func(tuples):
    for a, b in tuples:
        # do something for a and b
        result.append((c,d))
    return result

output = []
output.append(func(tups))

edited Feb 3, 2020 at 16:53

answered Jan 22, 2020 at 4:49

user11955706

Comments

funnydman · Accepted Answer · 2020-01-22 20:34:16Z

0

Just do this with list comprehensions:

tups = [(1,"a"),(2,"b"),(5,"t")]

print([(obj[1], obj[0]) for obj in tups])

# [('a', 1), ('b', 2), ('t', 5)]

answered Jan 22, 2020 at 20:34

funnydman

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