How to check all elements in array use jQuery

Question

I working with array, and i have array with numbers:

var array = [0,10,12,23,56,111,35,66,77,124,54];

As u can see i have number, from this numbers is bigger 124, and i want to return this number.

i try to create some func:

 var bigestValue = array.reduce(function (a, b) { return a > b ? a : b; })
if (bigestValue <= 100) {
        return 100;
    }

But when script is updating it's return for me last values

An array is a data type of JavaScript. Why would you want to use jQuery for that? Just use a simple for loop. — Andreas
– Andreas, Commented Jan 23, 2020 at 12:36
[0,10,12,23,56,111,35,66,77,124,54].find(num => num > 100); — Roberto Zvjerković
– Roberto Zvjerković, Commented Jan 23, 2020 at 12:36
[0,10,12,23,56,111,35,66,77,124,54].sort((a, b) => a > b ? -1 : 1)[0] — Roberto Zvjerković
– Roberto Zvjerković, Commented Jan 23, 2020 at 12:39
[0,10,12,23,56,111,35,66,77,124,54].reduce((max, num) => num > max ? num : max, Number.MIN_SAFE_INTEGER) — Roberto Zvjerković
– Roberto Zvjerković, Commented Jan 23, 2020 at 12:41

Sarfraaz · Accepted Answer · 2020-01-23 12:47:18Z

1

You can get Max number from array using

var array = [0,10,12,23,56,111,35,66,77,124,54];
var max = array.reduce((a,b)=> a > b ? a : b,0);

console.log(max);

If you want to filter array by getting only elements bigger than 100, then

var array = [0,10,12,23,56,111,35,66,77,124,54];
var maxArr = array.filter((a)=> a > 100);

console.log(maxArr);

answered Jan 23, 2020 at 12:47

Sarfraaz

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3 Comments

Sarfraaz Over a year ago

Glad to help, Please mark the answer as accepted so it would help others facing similar issue.

Roberto Zvjerković Over a year ago

Not only did you just repeat what I have already said in the comments, but your solution doesn't even work for negative numbers.

Sarfraaz Over a year ago

With all due respect, I did post an answer as requested by the author, Nowhere it was mentioned that he wanted this to work for negative numbers, It's approved from author for a reason

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