i have the following list with duplicate values and i need to check if the values is duplicated print it else skip it
List lst = ["AA","BB","BBB","AA"];
what should printed is :
AA
Thanks ;
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1Be sure to include a brief overview of what you have tried and/or what research you have done in your question's post.chris– chris2020-01-25 14:31:12 +00:00Commented Jan 25, 2020 at 14:31
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3 Answers
Would this work for you?
List list = ["AA", "BB", "BBB", "AA"];
List distinctList = list.toSet().toList();
void main() {
for (int i = 0; i < distinctList.length; i++) {
list.remove(distinctList[i]);
}
//// or you could use a "for in" like this:
// for (var item in distinctList) {
// list.remove(item);
// }
print(list.toSet().toList());
}
Or using
forEach() on the Set
List list = ['AA', 'BB', 'BBB', 'AA'];
void main() {
list.toSet().forEach((item) => {list.remove(item)});
print(list.toSet().toList());
}
Comments
lst.where((e) => lst.where((element) => element == e).length > 1).toSet().toList();
One Liner
Comments
List lst = ["AA","BB","BBB","AA"];
int duplicateDetectedCount = -1;
String duplicateItem = "";
for(String item in lst){
for(String innerItem in lst){
if(item == innerItem){
duplicateDetectedCount++;
if(duplicateDetectedCount == 1){
duplicateItem = innerItem;
}
}
}
}
print(duplicateItem); // prints AA
