Prevent to change some string from Google Closure Compiler?

Question

Have this code:

var a = 'Start';
var b = ' here';
return (document.querySelectorAll + "").toString().toLowerCase().indexOf(a + b) == -1;

After Google Closure Compiler, this code will be:

return (document.querySelectorAll + "").toString().toLowerCase().indexOf('Start here') == -1;

How to prevent changing this string because I don't need in parameter of indexOf 'Start here', very important that will be exactly 'a + b'? Do I have specific keys above this code that will explain GCC to not compile this code/string?

If you want the paramter of indexOf to be the string a + b then why not use 'a + b' instead of a + b in indexOf ? — Nick Parsons
– Nick Parsons, Commented Jan 26, 2020 at 9:30
Because I need that my code was not be parsed by some systems. They blocking my code with regex and I can't do anything — SkyStar
– SkyStar, Commented Jan 26, 2020 at 9:42
I need to change 'Start here' to 'Start' + ' here'. But compiler returning to me previous value @NickParsons — SkyStar
– SkyStar, Commented Jan 26, 2020 at 9:44

CertainPerformance · Accepted Answer · 2020-01-26 11:06:59Z

2

You can use the experimental @noinline annotation which:

Denotes a function or variable that should not be inlined by the optimizations.

To keep both a and b preserved, use:

function x() {
  /** @noinline */
  var a = 'Start';
  /** @noinline */
  var b = ' here';
  return (document.querySelectorAll + "").toString().toLowerCase().indexOf(a + b) == -1;
}

Result:

function x(){var a="Start",b=" here";return-1==(document.querySelectorAll+"").toString().toLowerCase().indexOf(a+b)};

Demo

(Note that since document.querySelectorAll + "" evaluates to a string already, you don't need to call toString on it again - you can leave that part off if you want)

answered Jan 26, 2020 at 11:06

CertainPerformance

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