I am new in python and need help with short code snippet below:
x=5
print(not x<=6)
Why the result is False? I think in the next way: not x is False, 0. Then 0 is less than 6. It's True.
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How about thinking in this way: x<=6 is True; not True is False. ?Austin– Austin2020-01-28 05:18:10 +00:00Commented Jan 28, 2020 at 5:18
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First the mathematical expression will be evaluated , i.e, x<=6 , and then the operator . Here, x<=6 is True . Therefore , negation (not) of True is False.Sarthak Gupta– Sarthak Gupta2020-01-28 05:21:17 +00:00Commented Jan 28, 2020 at 5:21
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@Austin I think code must be like that: not(x<=6). But in my variant it is: not x. This causes me problem.Oleksandr– Oleksandr2020-01-28 05:24:17 +00:00Commented Jan 28, 2020 at 5:24
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The 'not' is a Logical operator in Python that will return True if the expression is False. Just like the "!" in java. In your case, x<=6 is True, "not" operator will reverse the result so it will return False.law rence– law rence2020-01-28 05:25:27 +00:00Commented Jan 28, 2020 at 5:25
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1 Answer
You have set x equal to 5. This means that when you logically check if x is less than or equal to 6, it will be True. Since you have not there, it cancels the True to make it False, therefore printing False.
I think you may have got your operator precedence mixed up:
<, <=, >, >=, !=, == all take precedence over not
