Append element into nested list based on the index of the nested list

Question

I have a nested list which looks like this:

l = [[['0.056*"googl"'], ['0.035*"facebook"']], #Index 0
    [['0.021*"mensch"'], ['0.012*"forsch"']], #Index 1
    [['0.112*"appl"'], ['0.029*"app"']], # Index 2
    [['0.015*"intel"'], ['0.015*"usb"']]] #Index 3

Now I want to append the Index (and the word Topic) of the sublists into the individual sublists like this:

nl = [[['0.056*"googl"', 'Topic 0'], ['0.035*"facebook"', 'Topic 0']], 
     [['0.021*"mensch"', 'Topic 1'], ['0.012*"forsch"', 'Topic 1']], 
     [['0.112*"appl"', 'Topic 2'], ['0.029*"app"', 'Topic 2']], 
     [['0.015*"intel"', 'Topic 3'], ['0.015*"usb"', 'Topic 3']]]

How can I do this?

Sorry my bad, I removed them with regex in my code. Will change the OP. — gython
– gython, Commented Jan 28, 2020 at 12:34

U13-Forward · Accepted Answer · 2020-01-28 11:51:27Z

2

Use:

nl = [[[*x, 'Topic %s' % idx] for x in i] for idx, i in enumerate(l)]

Or use:

nl = [[x + ['Topic %s' % idx] for x in i] for idx, i in enumerate(l)]

And now:

print(nl)

Is:

[[['0.056*"googl"', 'Topic 0'], [' 0.035*"facebook"', 'Topic 0']], [['0.021*"mensch"', 'Topic 1'], [' 0.012*"forsch"', 'Topic 1']], [['0.112*"appl"', 'Topic 2'], [' 0.029*"app"', 'Topic 2']], [['0.015*"intel"', 'Topic 3'], [' 0.015*"usb"', 'Topic 3']]]

answered Jan 28, 2020 at 11:51

U13-Forward

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2 Comments

gython Over a year ago

Hi @U10 -Forward, thanks for your answer. One more question: How would I have to change the code if the sublists looked like this: [[['0.056', 'googl']], [['0.035', 'facebook']]] ?

U13-Forward Over a year ago

@gython ask a new question

Guy · Accepted Answer · 2020-01-28 11:53:51Z

1

You can do it with for loop

for i in range(len(l)):
    l[i][0].append(f'Topic {i}')
    l[i][1].append(f'Topic {i}')

answered Jan 28, 2020 at 11:53

Guy

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