How to parse a date and only the date from a `date_string` in python?

Question

I have a variable containing a string from which I want to parse the date. I tryed this:

import datetime
date_string = "July 2010"
parsed_date = datetime.datetime.strptime(date_string, "%B %Y")
print parsed_date
# datetime.datetime(2010, 7, 1, 0, 0))

I assume the 1 is added by datetime, because a date must have a day? But why are there two zeroes? I assume this shall be the time? Is there a way to avoid the time? I only want the date.

ThiefMaster · Accepted Answer · 2011-05-14 08:57:17Z

4

Simply call .date() on the datetime object. This returns a date object.

In [5]: dt
Out[5]: datetime.datetime(2010, 7, 1, 0, 0)
In [6]: dt.date()
Out[6]: datetime.date(2010, 7, 1)

For your other subquestions:

Yes, the 0, 0 is the time.
A date always has year, month and day (with 1 <= day <= 31).

answered May 14, 2011 at 8:57

ThiefMaster

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1 Comment

Aufwind Over a year ago

Just to complete my questions and eliminate my doubts. :-) Are my assumptions right?

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