I have a numpy array like this:
nparray = array([1.])
How can I get the '1'?
Thanks!
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Check this out - docs.scipy.org/doc/numpy/reference/generated/numpy.where.htmlNavidk– Navidk2020-02-04 06:08:07 +00:00Commented Feb 4, 2020 at 6:08
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3 Answers
In [7]: np.array([1.0])
Out[7]: array([1.])
For a single item array:
In [8]: np.array([1.0]).item()
Out[8]: 1.0
In [9]: np.array([1.0]).tolist()
Out[9]: [1.0]
For a single item 1d array:
In [10]: np.array([1.0])[0]
Out[10]: 1.0
Note that the type of the selection differs with the method. Often that doesn't matter.
In [11]: type(Out[10])
Out[11]: numpy.float64
In [12]: type(Out[8])
Out[12]: float
In [13]: type(Out[9][0])
Out[13]: float
If the array is 0d, item is best
In [14]: np.array(1.0).item()
Out[14]: 1.0
In [15]: np.array(1.0)[0]
---------------------------------------------------------------------------
IndexError Traceback (most recent call last)
<ipython-input-15-23b6eb4e1c33> in <module>
----> 1 np.array(1.0)[0]
IndexError: too many indices for array
In [16]: np.array(1.0)[()]
Out[16]: 1.0
To get an integer, instead of a float, you have to do an int conversion at some point, either in the array (with astype) or after.
1 Comment
NoBugs
Watch out, does not work with NDArray - gluon.mxnet.io/chapter01_crashcourse/ndarray.html#Watch-out! if you are using their library.
int(nparray[0])
hope it helps!
Comments
You can get it by passing the index such as
nparray[0]
