Cannot append to my list without getting a nonetype object error

Question

str1 = []
x = sentence.lower()
x = x.strip('.')
x = x.strip('!')
lsent = x.split()
for e in lsent:
    if e != 'the' and e != 'is' and e != 'if' and e != 'it':
        str1 = str1.append(e)
str1 = " ".join(str1)
print(str1)

Heres my code. When I try to append an item to the end of the list it tells me str1 is a nonetype object even though I made it a list in the first row.

Any help is appreciated I'm thoroughly confused.

Does this answer your question? Why does append() always return None in Python? — Javier
– Javier, Commented Feb 5, 2020 at 4:29

jarthur · Accepted Answer · 2020-02-05 04:14:31Z

3

Python List.append() method returns the value of None. What you are trying to do, can be done simply by changing

str1 = str1.append(e)

to

str1.append(e)

answered Feb 5, 2020 at 4:14

jarthur

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Javier · Accepted Answer · 2020-02-05 04:24:09Z

1

The append method to a List modifies it in place and returns a None. Change it for

str1.append(e)

And just to be fair with other users, this was answered at least a couple of times. ;-) For instance, https://stackoverflow.com/a/16641831/2705572

P.S.: In any case, it is always good to answer :-) Welcome to our Community!

edited Feb 5, 2020 at 4:24

answered Feb 5, 2020 at 4:16

Javier

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