How to convert a File URL into binary data (multipart/form-data) for upload

Question

I would like to upload a file from URL using Python requests.post

Would anyone guide me how to convert a file URL into binary data (multipart/form-data) for upload?

I have tried with these code but it return failed.

file = requests.get(file_url, stream=True)
file_upload = {
            "name": file_name,
            "uploadfile": file.content 
            }
headers = {
            'Content-Type': 'multipart/form-data',
            'Accept': 'application/json'
          }
requests.post('{POST_URL}', files=file_upload, headers=headers)

POST_URL is external service and only support PDF file (string($binary)).

{
    "name": string
    "uploadfile": string($binary) 
}

Thank you so much.

Jatin Bansal · Accepted Answer · 2020-02-07 07:45:02Z

1

As per python-requests documentation (Here), if you specify files parameter in requests.post, it will automatically set requests content-type as 'multipart/form-data'. So, you just need to omit the headers part from your post request as:

import requests

file = requests.get('{FILE_URL}', stream=True)

with open({TEMP_FILE}, 'wb') as f:
    for chunk in response.iter_content(chunk_size=1024):
        if chunk:
            f.write(chunk)

binaryContent = open({TEMP_FILE}, 'rb')

a = requests.post('{POST_URL}', data={'key': binaryContent.read()})

Update: You can first try downloading your file locally and posting its binary data to your {POST_URL} service.

edited Feb 7, 2020 at 7:45

answered Feb 7, 2020 at 5:56

Jatin Bansal

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9 Comments

スーパーマン Over a year ago

Thank you so much for your comment, I tried to omit the content-type but I got the error 415 - UNSUPPORTED MEDIA TYPE

Jatin Bansal Over a year ago

@グエントォ, I have updated my answer, please check if it solves your issue.

スーパーマン Over a year ago

Unlucky me that it still not working. I tried with local file also.

スーパーマン Over a year ago

{POST_URL} service return {'error': 'bad_request', 'message': 'invalid upload'}

Jatin Bansal Over a year ago

If possible, can you give the {POST_URL} here for testing?

|

L Tyrone · Accepted Answer · 2024-03-26 07:03:03Z

0

Here's a simple function that can appropriately send your file to any endpoint you want:

def upload_file(file_path, token):
"""Upload the file and return the response from the server."""
headers = {'Authorization': f'Bearer {token}'}
with open(file_path, "rb") as file:
    files = {'file': (os.path.basename(file_path), file, 'application/pdf')}
    response = requests.post(post_url, headers=headers, files=files)
response.raise_for_status()
return response

Python will automatically pick the multipart/form-data content type for you. All you need to do is supply the file correctly. Using the Authorization is optional, but I added it in case the API you want to post to requires one.

edited Mar 26, 2024 at 7:03

L Tyrone

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answered Mar 25, 2024 at 12:22

FLOROID

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