Similar to this problem: convert an integer number into an array but I don't know how this is implemented in MIPS.
Is there a way to convert an integer digits into an array (i.e. 45 -> array[0] = 5 ; array [1] = 4)?
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Yes, it can be done. This is not special to MIPS, so try a C version first, once you have that working, then translate to assembly.Erik Eidt– Erik Eidt2020-02-08 17:27:50 +00:00Commented Feb 8, 2020 at 17:27
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1 Answer
Of course there is a way. You divide by 10 for every digit in your number and store the remainder in your array. This will probably do the job:
.data
array: .word
.text
.globl main
main:
la $t9, array
li $t1, 45 #number to be stored
li $t2, 10 #base 10
while:
beq $t1, $0, end
div $t1, $t2 # divide by ten, $hi = $t1/$t2, $lo = $t1 mod $t2
mfhi $t3
mflo $t1
sw $t3, 0($t9) #store word into array
addi $t9, $t9, 4 #increment array index
j while
end:
