Delete data in response array with php

So, if what are you saying is correct it looks like you are already properly filtering your content to exclude those with the unwanted ids. Good job! Now, you want the JSON back that also contains your pagination data. First let's step through your code to see how we ended up here:

$response = ….get(url)………

$list = $response->getBody()[‘content’];

Right here, in the first two lines, we see that you have selected ONLY the content from your response body and stored it in $list.

$collection = collect($list);

$filtered = $collection->filter(function ($item) [
    return auth()->user->permission($item['id'])
]);

Now, you're taking that content and filtering it based on id.

Return [‘content’ => $filtered];

And, lastly, you are returning the filtered content. So, nothing has been deleted at all - you've just pulled out the content, filtered it, and returned it. Your pagination data is still sitting right where you left it. In order to get the JSON you want to return you could adjust the way you are pulling out content and filtering it, but since I don't know many details of what you're doing or why and your filter is already working my instinct is why bother? You could just take your pagination data and combine it with your filtered content and then you would have exactly what you're looking for:

$response = ….get(url)………

$list = $response->getBody()[‘content’];
$pagination = $response->getBody()[‘pagination’];

$collection = collect($list);

$filtered = $collection->filter(function ($item) [
    return auth()->user->permission($item['id'])
]);

$alldata = // combine your pagination and filtered objects 

Return [‘data’ => $alldata];

Note that I did not show how to combine pagination and the filtered content - this is because I'm not sure what type of objects you've got at this point. Since your sample output is not really proper JSON I'm not sure if pagination really is supposed to be a list/array or if it's just the way you've written your examples, I'm not sure if these are strings or if they've been parsed, etc. So strings would require appending one to the other, collections would use combine(), and so on.

Your array is an invalid array ! So I couldnt try it, as I mentioned in comment!

What I understand from reading all your edits, Here some examples how you can remove id 2 from array in php:

Before starting : we have an option to ignore id 2 in php where clause like so

SELECT * FROM table WHERE id NOT IN (2)

OR 

SELECT FROM table WHERE id <> 2 

You can ignore id 2 when querying then you will have an array without id 2, lets contine with arrays

if you want to remove a specific value in array do the following.

Remove from an Associative Array

   $YourArray = array("id"=>"2","name"=>"somename");

    //use array key exist to find if id exist

    $test = array_key_exists("id",$YourArray);
      if($test == 2){
        unset($YourArray['id']); //Here you unset id 2
      }
    print_r($YourArray); //result of new array

Second solution with multdimential arrays:

// PHP program to creating two  
// dimensional associative array 
$data = array( 

    // Ankit will act as key 
    "paginate" => array( 

        // Subject and marks are 
        // the key value pair 
        "id" => 1, 
        "name" => "Widget #1",  
        "uri"=> "/products/1"
    ), 

    // Ram will act as key 
    "content" => array( 

        // Subject and marks are 
        // the key value pair 
        "id" => 2, 
        "name" => "Widget #1",  
        "uri"=> "/products/1"
    ),  
); 

echo "Display Marks: \n"; 


foreach ($data as $key => $subArr) {
    if($subArr['id'] == 2){
    unset($subArr['id']);
    $data[$key] = $subArr; 
    }
}
print_r($data); 

Here is the demo : https://3v4l.org/mvZPN

If you want to remove id and all its elements in array : array_filter(); used

$test = array_filter($data, function($data) { return $data['id'] != 2; });

print_r($test);

Here is the demo : https://3v4l.org/UgNqu