help in perl regex using command line

Question

I have regex expression:

echo "(1508,'2011-02-28','pc','postroll','ai-postroll','HT','','',16),(1508,'2011-02-28','pc','postroll','ai-postroll','MU','','',11),(1508," | perl -pe "s|,(\d+)\)|,'',($1)\)|g"

I am trying to replace the number before closing parenthesis with an extra value.
So '',16) would be replaced by ,'',''16) .

I am finding issue that $1 is not getting replaced.Please let me know what is that I am doing wrong.

Thanks in advance

Brian · Accepted Answer · 2011-05-16 15:05:25Z

5

Since you used double-quotes, bash will try to substitute a value for $1. Try replacing it with \$1.

answered May 16, 2011 at 15:05

Brian

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