Prompting an input in bash script should executes an bash function

Question

I would like to get an output based on the input we provided. For Example,

if I selected 1 it should take the 1st element in the array and the output should be My name is test

if I selected 2 it should take the 2nd element in the array and the output should be My name is test1

similarly, if I select all the output should be My name is test My name is test1 My name is test2 My name is test3

 a=("test" "test1" "test2" "test3")

testfunction() {
        echo My name is $a
}

echo "Enter a number"
select number in "test" "test1" "test2" "tes3" "all"; do
    case "$number" in
        test)
            testfunction "${a[0]}"; break;;
        test1)
            testfunction "${a[1]}"; break;;
        test2)
            testfunction "${a[2]}"; break;;
        test3)
            testfunction "${a[3]}"; break;;
        all)
            testfunction "${a[@]}"; break;;
    esac
done

Can someone please help me with this?

Why do you need a separate case for number in 1,2,3,4? Just verify that if $number is numeric and in the correct range, and then call testfunction "${a[$number]}". — user1934428
– user1934428, Commented Feb 19, 2020 at 8:22

Ayush Sinha · Accepted Answer · 2020-02-19 06:08:22Z

1

As pointed out by other answers, you should use $1 in your testfunction(). Additionally, you can use a for loop to get your desired output when you select all as your input.

a=("test" "test1" "test2" "test3")

testfunction() {
        echo My name is $1
}

echo "Enter a number"
select number in "test" "test1" "test2" "test3" "all"; do
    case "$number" in
        test)
            testfunction "${a[0]}"; break;;
        test1)
            testfunction "${a[1]}"; break;;
        test2)
            testfunction "${a[2]}"; break;;
        test3)
            testfunction "${a[3]}"; break;;
        all)
            for i in "${a[@]}"; do testfunction "${i}"; done
            break;;
    esac
done

edited Feb 19, 2020 at 6:08

answered Feb 19, 2020 at 5:25

Ayush Sinha

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Comments

Naveen Hiremath · Accepted Answer · 2020-02-19 04:59:00Z

0

You should be printing $1 instead of $a in your testfunction.

testfunction() {
        echo My name is $*
}

EDIT: Changing it to consider "all" case as well.

edited Feb 19, 2020 at 4:59

answered Feb 19, 2020 at 4:52

Naveen Hiremath

3611 silver badge8 bronze badges

2 Comments

Chintu Over a year ago

It is only taking the first element in the array even if I enter the all in the prompt.

Naveen Hiremath Over a year ago

My bad.... I didn't consider "all" case. Use $* instead of $1.

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