How to execute a non-blocking script in python and get its return code?

Question

I am trying to execute a non-blocking bash script from python and to get its return code. Here is my function so far:

def run_bash_script(script_fullname, logfile):
    my_cmd = ". " + script_fullname + " >" + logfile +" 2>&1"
    p = subprocess.Popen(my_cmd, shell=True)
    os.waitpid(p.pid, 0)
    print(p.returncode)

As you can see, all the output is redirected into a log file, which I can monitor while the bash process is running.

However, the last command just returns 'None' instead of a useful exit code.

What am I doing wrong here?

pynexj · Accepted Answer · 2020-02-19 09:31:13Z

1

You should use p.wait() rather than os.waitpid(). os.waitpid() is a low level api and it knows nothing about the Popen object so it could not touch p.

answered Feb 19, 2020 at 9:31

pynexj

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1 Comment

Alex Over a year ago

Thanks, it looks like that was exactly what I needed!

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