Javascript - construct an array with elements repeating from a string

Question

Suppose there is a string aba and a limit 5. How can i create an array with elements repeating from the string till the limit is reached ?

e.g. string = "aba" and limit = 5 will give new array ["a","b","a","a","b"]

As of now, my array fills with all characters then blank strings are repeated for the left indexes.

function repeatedString(s, n) {
  let arr = [];
  for (let i = 0; i < n; i++) {
    let char = s.charAt(i);
    arr.push(char);
  }
  console.log(arr);
}

repeatedString("aba", 5)

Nick Parsons · Accepted Answer · 2020-02-24 09:40:05Z

5

Your code is almost there. You just need to let your index you use in .charAt() wrap back to 0 when you reach the length of the string. This can be done using the remainder operator (%) with the length of the string like so:

function repeatedString(s, n) {
  let arr = [];
  for (let i = 0; i < n; i++) {
    let char = s.charAt(i % s.length);
    arr.push(char);
  }
  console.log(arr);
}

repeatedString("aba", 5)

answered Feb 24, 2020 at 9:40

Nick Parsons

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Nina Scholz · Accepted Answer · 2020-02-24 09:41:54Z

2

You could get an array of a padded string.

var string = 'aba',
    limit = 5,
    result = Array.from(''.padStart(limit, string));

console.log(result);

answered Feb 24, 2020 at 9:41

Nina Scholz

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Comments

Rajesh Dixit · Accepted Answer · 2020-02-24 09:41:47Z

1

You can use string functions for this:

Calculate the times given string needs to be repeated.
Repeat the string and extract n length string from it
Split this string by individual characters

function repeatedString(s, n) {
  const repeatCount = Math.ceil(n/s.length);
  return s.repeat(repeatCount).slice(0, n).split('');
}

console.log(repeatedString("aba", 5))

answered Feb 24, 2020 at 9:41

Rajesh Dixit

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