What I can do:
const val = array.find((val) => <condition>);
const index = array.indexOf(val);
What I'd like to do:
const { val, index } = array.someFunc((val, index) => <condition> && { val, index });
Anything like this out there? some() is reduced to a boolean, and find() just returns the array element, but neither fit the use case.
There's no built-in for this. But Object.entries could be used:
const array = ['foo', 'bar', 'baz'];
const [ index, val ] = Object.entries(array).find(([i, v]) => v === 'baz');
console.log(index, val);
There is no built in prototype to do that for an array, so you will need to create a wrapper function.
let numbers = [10, 20, 30, 40, 50];
function myFunction(array, find) {
const val = array.find((val) => find == val);
const index = array.indexOf(val);
return { val, index };
}
console.log(myFunction(numbers, 30));Most people's least favorite option is to extend Array.prototype, so you can call the function array.myFunction(40)
let numbers = [10, 20, 30, 40, 50];
Array.prototype.myFunction = function(find) {
const val = this.find((v) => find == v);
const index = this.indexOf(val);
return { val, index };
}
console.log(numbers.myFunction(30));
mapthenfind?Array.findIndex()that would reduce some effort